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# CPS: Solution To Fertilizer Assignment (To Be Submitted February 14) CPS 202 Assignment On Fertilizer To Be Submitted on February 14, 2023.

## Answers To Number 1 & 2 Below; ## Answers To Question 3 & 4 Below ### 6. Determine The Quantity Of SSP Required To Supply 55kgP2O5/ha

Solution

Q = Unknown, R = 55kg, C = 18

Q = 55 × 100/18

Q = 305.6kg SSP/ha

### 7. Determine The Quantity Of SSP Required To Supply At 45kg/ha to 25m by 95m Farm Land

Solution

Area Of Land = Length × Breadth

25m × 95m = 2375m²

So, Q = R × 100/C

= 45 × 100/18

= 250kg SSP/ha

Meaning 1ha =

10,000m² = 250kg SSP/ha

2375m² = Unknown

Cross Multiply

250 × 2375 = 10,000 Unknown

250 × 2375/10,000 = 59.4kg SSP/2375m²

### 9. Determine The Quantity Of Urea required to supply Nitrogen to 600kg soil at 40kgN/ha

Solution

Calculate for 1 ha of land

Q = 40 × 100/45

Q = 4000/45

Q = 88.9kg urea/ha

2,000,0000 of soil = 88.9kg Urea/ha

600kg Soil = Unknown

Now Cross Multiply

600kg × 88.9kg Urea/ha = 2,000,000 Unknown

### 10. Determine The Quantity Of TSP Required To Supply Phosphorus at 60kgP/ha To 50kg Soil.

Solution

Q = ?, R = 60kgp/ha, C = 20%

Q = 60 × 100/20 = 300 KgTsp/ha.

So,

1 ha (2,000,000 Of Soil) = 300kgTSP/ha

50kg = Unknown

Cross multiply

300kg × 50 = 2,000,000 unknown

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