CPS: Solution To Fertilizer Assignment (To Be Submitted February 14)

CPS 202 Assignment On Fertilizer To Be Submitted on February 14, 2023.

The Answers Are Straight Forward And Please Use Your Calculator To Crosscheck The Answers.

Answers To Number 1 & 2 Below;

Answers To Question 3 & 4 Below

6. Determine The Quantity Of SSP Required To Supply 55kgP2O5/ha

Solution

Q = Unknown, R = 55kg, C = 18

Q = 55 × 100/18

Q = 305.6kg SSP/ha

7. Determine The Quantity Of SSP Required To Supply At 45kg/ha to 25m by 95m Farm Land

Solution

Area Of Land = Length × Breadth

25m × 95m = 2375m²

So, Q = R × 100/C

= 45 × 100/18

= 250kg SSP/ha

Meaning 1ha =

10,000m² = 250kg SSP/ha

2375m² = Unknown

Cross Multiply

250 × 2375 = 10,000 Unknown

250 × 2375/10,000 = 59.4kg SSP/2375m²

9. Determine The Quantity Of Urea required to supply Nitrogen to 600kg soil at 40kgN/ha

Solution

Calculate for 1 ha of land

Q = 40 × 100/45

Q = 4000/45

Q = 88.9kg urea/ha

2,000,0000 of soil = 88.9kg Urea/ha

600kg Soil = Unknown

Now Cross Multiply

600kg × 88.9kg Urea/ha = 2,000,000 Unknown

Answer Is 0.027kg.

10. Determine The Quantity Of TSP Required To Supply Phosphorus at 60kgP/ha To 50kg Soil.

Solution

Q = ?, R = 60kgp/ha, C = 20%

Q = 60 × 100/20 = 300 KgTsp/ha.

So,

1 ha (2,000,000 Of Soil) = 300kgTSP/ha

50kg = Unknown

Cross multiply

300kg × 50 = 2,000,000 unknown

Answer Is 0.0075KgTSP

KINDLY NOTE, THE REST OF THE ANSWERS WILL BE UPDATED BEFORE 7PM ON SUNDAY.